Question

consecutive odd integer problem
find two odd integers the sum of whose squares is 130.
(sq)=squared

let x= 1st odd int
let x+2=2nd odd int

(2x+2)(2x+2)=130
4x(sq) + 4x+ 4x +4=130
4x(sq) + 8x -126= 0

2(2x(sq)+4x-63)=0
My question: WHAT ARE THE TWO DARN #s!!!

Answer 1

The squares of the first few odd integers are: 9, 25, 49, 81, 121

Two pairs of these add up to 130, but the square roots of which two of these are consecutive?

Answer 2

the two numbers to factor the equation.
pair of #s that multiplies to -126
and the same pair that adds to a 4.

Answer 3

consecutive odd integer problem
find two odd integers the sum of whose squares is 130.
(sq)=squared

let x= 1st odd int
let x+2=2nd odd int

x^2 + (x + 2)^2 = 130
x^2 + x^2 + 4x + 4 = 130
2x^2 + 4x - 126 = 0
x^2 + 2x - 63 = 0

I bet you can find the answers now.