How about (0,12) and (9,0) ?
There are other possibilities also.
Find two points, one on the horizontal axis and one on the vertical axis, such that the distance between these two points equals 15.
NEED HELP PLEASE!!
3 answers
yes, these two points does equal to 15, but how did you find these points?
I thought of creating a 3:4:5 (ratio of sides) right triangle, with the hypotenuse equal to 15. The 3:4:5 ratio stays the same.
I could have also chosen
(0, 15/sqrt2) and (15/sqrt2, 0)
or
(-3,0) and (0,-4)
and many others.
I could have also chosen
(0, 15/sqrt2) and (15/sqrt2, 0)
or
(-3,0) and (0,-4)
and many others.
1 answer