Find two consecutive odd integers such that their product is 39 more than 9 times their sum?
6 answers
HELP HAS TO BE DONE BY 12
solve for x and a tutor will check your work.
I already gave you a hint the last time you posted this question.
I already gave you a hint the last time you posted this question.
so, using the previous suggestion,
x(x+2) = 39 + 9(x + x+2)
Now just finish it off ...
x(x+2) = 39 + 9(x + x+2)
Now just finish it off ...
Let the two odd consecutive numbers be x and x+2
x(x+2) - 9(x + x+2) = 39
x^2 + 2x - 18x - 18 = 39
x^2 - 16x - 57 = 0
(x -19)(x + 3) = 0
x = 19 or x = -3
the two consecutive odds are either 19 and 21 OR -3 and -1
check 19,21
product = 399
9 times their sum = 9(40) = 360
yes, their product is 39 more than 9 times their sum
check -3, -1
their product is 3
9 times their sum is 9(-4) = -36
and 3 is greater than -36 by 39
so both of my answers are correct
x(x+2) - 9(x + x+2) = 39
x^2 + 2x - 18x - 18 = 39
x^2 - 16x - 57 = 0
(x -19)(x + 3) = 0
x = 19 or x = -3
the two consecutive odds are either 19 and 21 OR -3 and -1
check 19,21
product = 399
9 times their sum = 9(40) = 360
yes, their product is 39 more than 9 times their sum
check -3, -1
their product is 3
9 times their sum is 9(-4) = -36
and 3 is greater than -36 by 39
so both of my answers are correct
to the suggestion above. When I Solve it I get -3,19 but its saying its wrong
You are not getting the right conclusion
the value of x is indeed -3 and 19
but I called the two numbers x and x+2
so if you use x = 19, your two consecutive odds are 19 and 21
if you use x = -3, you would have -3 and -1
I verified both answers, did you not read my solution???
the value of x is indeed -3 and 19
but I called the two numbers x and x+2
so if you use x = 19, your two consecutive odds are 19 and 21
if you use x = -3, you would have -3 and -1
I verified both answers, did you not read my solution???
1 answer