Find two consecutive even intergers such that the square of the smaller is 10 more than the larger.

Answer 1

first number --- x
next consecutive even number --- x+2

x^2= x+2 + 10
x^2 - x - 12 = 0
(x-4)(x+3) = 0
x = 4 or x = -3 , but x has to be even

x = 4
numbers are 4 and 6

check: square of smaller is 16
10 more than the larger is 10+6 = 16
Yeah!