n-2, n, n+2
4(n-2) - n = 12 + 2(n+2)
4 n - 8 - n - 12 - 2n - 4 = 0
n - 24 = 0
n = 24
22 , 24, 26
Find three consecutive positive even integers such that four times the first decreased by the second is 12 more than twice the third.
1 answer