Find three consecutive intergers such that the product of the first and the second is two more than three times the third.

Answer 1

suppose no are
x, x+1, x+2

Equal to condition

{(x)*(x+1)}=3(x+2)+2
-> x^2+x =3x+6+2
-> x^2-2x-8=0
-> x= 4 and -2

so no are 4, 5 and 6