The product of two consecutive intergers is 56. Find the intergers.
3 answers
7 and 8. 7times8=56
let the integers be x and x+1
x(x+1) = 56
x^2 + x - 56 = 0
(x+8)(x-7) = 0
x = -8 or x = 7
the 2 number are either 7 and 8
or -8 and -7
x(x+1) = 56
x^2 + x - 56 = 0
(x+8)(x-7) = 0
x = -8 or x = 7
the 2 number are either 7 and 8
or -8 and -7
the sum of three consecutive even integers is 780. how do you figure that out.
1 answer