let u = x^2
then you have
u^2-7u-144 = 0
(u-16)(u+9) = 0
so u=16 or u=-9
that means that
x^2 = 16
x^2 = -9
ta-daaa!
Find the zeros
X^4-7x^2-144=0
The answer is x=4,−4,3i,−3i
Can someone help me with the steps
2 answers
x^4-7x^2-144=0
(x^2 - 16)(x^2 + 9) = 0
x^2 = 16
x = ± 4
or
x^2 = -9
x = ± 3i
(x^2 - 16)(x^2 + 9) = 0
x^2 = 16
x = ± 4
or
x^2 = -9
x = ± 3i