Find the X intercepts of each relation without graphing: Y=(x+4)(x-1) , y=-(x-3)(x+3) , y=-(x-2)(x+6) , y=-(x-5)(x-6)

Answer 1

To find the x-intercepts, we need to set y equal to zero and solve for x.

1. $y = (x+4)(x-1)$

Setting y = 0:

$0 = (x+4)(x-1)$

$x+4 = 0$ or $x-1 = 0$

$x = -4$ or $x = 1$

Therefore, the x-intercepts are -4 and 1.

2. $y = -(x-3)(x+3)$

Setting y = 0:

$0 = -(x-3)(x+3)$

$x - 3 = 0$ or $x + 3 = 0$

$x = 3$ or $x = -3$

Therefore, the x-intercepts are 3 and -3.

3. $y = -(x-2)(x+6)$

Setting y = 0:

$0 = -(x-2)(x+6)$

$x - 2 = 0$ or $x + 6 = 0$

$x = 2$ or $x = -6$

Therefore, the x-intercepts are 2 and -6.

4. $y = -(x-5)(x-6)$

Setting y = 0:

$0 = -(x-5)(x-6)$

$x - 5 = 0$ or $x - 6 = 0$

$x = 5$ or $x = 6$

Therefore, the x-intercepts are 5 and 6.