Find the voltage across each resistor in a series circuit. Note: R is the lowest value and all others are multiples of that value as indicated.
(there is no diagram for this circuit)
double battery cell = 15v
resistor1 = R
resistor2 = 2R
resistor3 = 4R
3 answers
15v x (the resistance of that one resistor) / (the sum of both resistors) .Solve
my answer is
1r+2r+4r=7r
15v(r/7r)
15v(2r/7r)
15v(4r/7r)
1r+2r+4r=7r
15v(r/7r)
15v(2r/7r)
15v(4r/7r)
See your 3:15 PM post.