Find the values of the six trigonometric functions of an angle in standard position if the point with coordinates (12, 5) lies on its terminal side?
Please explain how!
2 answers
I know the answer but I don't understand the process. ! If you could explain the process without the answers?!
plot the point (12,5) and join it to the origin.
draw a vertical line from the point to the x-axis
You now have a right-angled triangle with a base (x) of 12 and a height (y) of 5
Using Pythagoras, we can find the hypotenuse
h^2 = 12^2 + 5^2 = 169
h = 13
let the base angle be Ø
You should have learned the following definitions
sinØ = opposite/hypotenuse = 5/13
cosØ = adjacent/hypotenus = 12/13
tanØ = opposite/adjacent = 5/12
of course ...
cscØ = 13/5
secØ = 13/12
cotØ = 12/5
draw a vertical line from the point to the x-axis
You now have a right-angled triangle with a base (x) of 12 and a height (y) of 5
Using Pythagoras, we can find the hypotenuse
h^2 = 12^2 + 5^2 = 169
h = 13
let the base angle be Ø
You should have learned the following definitions
sinØ = opposite/hypotenuse = 5/13
cosØ = adjacent/hypotenus = 12/13
tanØ = opposite/adjacent = 5/12
of course ...
cscØ = 13/5
secØ = 13/12
cotØ = 12/5
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