Asked by rashed
Find the values of the six trigonometric functions for angle θ in standard position if a point with the coordinates (-3,-5) lies on its terminal side.
Answers
Answered by
Bosnian
In this case:
x = - 3 , y = - 5
r = √ ( x² + y² )
r = √ [ ( - 3 )² + (- 5 )² ]
r = √ ( 9 + 25 )
r = √34
sin θ = y / r = - 5 / √34
cos θ = x / r = - 2 / √34
sec θ = 1 / cos θ = - √34 / 2
csc θ = 1 / sin θ = - √34 / 5
tan θ = sin θ / cos θ = ( - 5 / √34 ) / ( - 2 / √34 ) = 5 / 2
cot θ = cos θ / sin θ = ( - 2 / √34 ) / ( - 5 / √34 ) = 2 / 5
x = - 3 , y = - 5
r = √ ( x² + y² )
r = √ [ ( - 3 )² + (- 5 )² ]
r = √ ( 9 + 25 )
r = √34
sin θ = y / r = - 5 / √34
cos θ = x / r = - 2 / √34
sec θ = 1 / cos θ = - √34 / 2
csc θ = 1 / sin θ = - √34 / 5
tan θ = sin θ / cos θ = ( - 5 / √34 ) / ( - 2 / √34 ) = 5 / 2
cot θ = cos θ / sin θ = ( - 2 / √34 ) / ( - 5 / √34 ) = 2 / 5
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