Asked by Anonymous
Find the values of the six trigonometric functions for ∠A in standard position determined by the point (63, 280). Enter your answers as fractions.
Answers
Answered by
Reiny
The point is in the 1st quadrant, so all our ratios will be positive
r^2 = 63^ + 280^2 = 82369
r =√82369 = 287
sinA = y/r = 280/287 = 40/41 , then cscA = 41/40
cosA = x/r = 63/287 = 9/41 , then secA = 41/9
tanA = y/x = 280/63 = 40/9 , then cotA = 9/40
r^2 = 63^ + 280^2 = 82369
r =√82369 = 287
sinA = y/r = 280/287 = 40/41 , then cscA = 41/40
cosA = x/r = 63/287 = 9/41 , then secA = 41/9
tanA = y/x = 280/63 = 40/9 , then cotA = 9/40
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