the vertex of a parabola is at the point
(-b/2a , c - b^2/4a)
so, you want
-11 + b^2/4 = 53
so solve for b. Check to be sure you get the right solution.
Find the values of b such that the function has the given maximum value.
f(x) = −x2 + bx − 11;
Maximum value: 53
2 answers
F(x) = -x^2 + Bx - 11.
Xv = h =-B/-2 = B/2.
-(B/2)^2 + B*B/2 - 11 = 53.
-B^2/4 + B^2/2 - 11 = 53,
-B^2/4 + 2B^2/4 - 11 = 53,
B^2/4 = 64,
B^2 = 256,
B = 16.
Xv = h = B/2 = 16/2 = 8.
V(h, k) = V(8, 53).
Xv = h =-B/-2 = B/2.
-(B/2)^2 + B*B/2 - 11 = 53.
-B^2/4 + B^2/2 - 11 = 53,
-B^2/4 + 2B^2/4 - 11 = 53,
B^2/4 = 64,
B^2 = 256,
B = 16.
Xv = h = B/2 = 16/2 = 8.
V(h, k) = V(8, 53).
1 answer