find the value of x and y. Write your answer as an ordered pair.

Question

(2b^4)^y/8b^x=2b^4
and
b^x-2/b^y+4=b^2

Answer 1

(2b^4)^y/8b^x=2b^4
(2^y b^4y) / (8 b^x) = 2b^4
2^(y-3) b^(4y-x) = 2^1 b^4
so
y-3 = 1
4y-x = 4
(x,y) = (12,4)

Do the other in like wise.