To identify the key parts of a parabola, we typically need the equation of the parabola. Since the equation was not provided, I'll guide you through the process assuming you have a standard parabola equation in the form \(y = ax^2 + bx + c\) or a similar form.
Steps to Identify Key Parts of the Parabola
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Vertex: To find the vertex, use the formula \(x = -\frac{b}{2a}\) to find the x-coordinate, then substitute back into the equation to find the y-coordinate.
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Zeros: The zeros (or roots) can be found by setting \(y = 0\) in the parabola's equation and solving for \(x\).
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Line of Symmetry: The line of symmetry for a parabola is a vertical line that passes through the vertex, given by the equation \(x = -\frac{b}{2a}\).
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Y-Intercept: The y-intercept occurs where \(x = 0\). Substitute \(x = 0\) into the equation to find the y-coordinate.
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Complete the Table: Substitute the given x-values into the function \(f(x)\) to find the corresponding y-values.
Example Walkthrough
Let's say the equation of the parabola is \(y = x^2 - 4x + 3\).
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Vertex: \[ x = -\frac{-4}{2 \cdot 1} = 2 \] Substituting \(x = 2\) into the equation: \[ y = 2^2 - 4 \cdot 2 + 3 = 4 - 8 + 3 = -1 \] Vertex = (2, -1)
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Lesser Zero (Finding the roots): \[ 0 = x^2 - 4x + 3 \implies (x-1)(x-3) = 0 \] Lesser zero = (1, 0)
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Other Zero: The other zero from the factored form: Other zero = (3, 0)
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Line of Symmetry: \[ x = 2 \]
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Y-Intercept: \[ f(0) = 0^2 - 4 \cdot 0 + 3 = 3 \] Y-intercept = (0, 3)
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Completing the Table: \[ \begin{array}{|c|c|} \hline x & f(x) \ \hline -1 & (-1)^2 - 4(-1) + 3 = 1 + 4 + 3 = 8 \ 0 & 3 \ 1 & 1^2 - 4(1) + 3 = 1 - 4 + 3 = 0 \ 3 & 0 \ 5 & 5^2 - 4(5) + 3 = 25 - 20 + 3 = 8 \ \hline \end{array} \]
Please provide the specific equation for your parabola, and I can give precise details based on that equation.