Find the value of x

Question

2x^(2/3) - x ^(1/3) -6 =0

Thanks for your help :)

Answer 1

Treat x^(1/3) as a new variable y, and factor the resulting equation
2y^2 -y -6 = 0
(2y +3)(y-2) = 0

y = x^(1/3) = -3/2 or 2

Now cube that for x.