Asked by SK
Find the value of tangent of angle A, given cos2A = 4/5, and A terminates in quadrant 2
Answers
Answered by
Damon
I am not going to do them all for you. Let's see you try.
Answered by
Lost in Trig
I have the same equation, so I will try. The "cos2A" is throwing me off. Since it is in QII it will be <90 and >180. Since it is a COS the value of theta should be x/r?
x in QII is negative so x=(-4)
r = 5
y = 3
Almost hate to go further if I am off
since TAN(theta)=y/x
TAN(theta)= 3/(-4)
here is where the "cos2A" throws me and I cant find any examples. Is it as simple as 2(3/5)?
Appreciate any clarity.
x in QII is negative so x=(-4)
r = 5
y = 3
Almost hate to go further if I am off
since TAN(theta)=y/x
TAN(theta)= 3/(-4)
here is where the "cos2A" throws me and I cant find any examples. Is it as simple as 2(3/5)?
Appreciate any clarity.
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