Asked by Anonymous
Find the exact value of the sine, cosine, and tangent of the angle 330 degrees.
I know the tangent is -(square root 3)/3, but how?
I know the tangent is -(square root 3)/3, but how?
Answers
Answered by
Bosnian
330 ° = 360 ° - 30 °
Circular functions:
sin ( 360 ° - theta ) = - sin theta
sin 330 ° = sin ( 360 ° - 30 ° ) = - sin 30 ° = - 1 / 2
cos ( 360 ° - theta ) = cos theta
cos 330 ° = cos ( 360 ° - 30 ° ) = cos 30 ° = sqroot 2 / 2
tan ( 360 ° - theta ) = - tan theta
tan 330 ° = tan( 360 ° - 30 ° ) = - tan 30 ° = - sqroot 3 / 3
Circular functions:
sin ( 360 ° - theta ) = - sin theta
sin 330 ° = sin ( 360 ° - 30 ° ) = - sin 30 ° = - 1 / 2
cos ( 360 ° - theta ) = cos theta
cos 330 ° = cos ( 360 ° - 30 ° ) = cos 30 ° = sqroot 2 / 2
tan ( 360 ° - theta ) = - tan theta
tan 330 ° = tan( 360 ° - 30 ° ) = - tan 30 ° = - sqroot 3 / 3
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