Question

find the value of a, if it exists, such that the following function is continuous at X = 2.

piecewise function
f(x)={x^2-3x+1, if x>2; a, if x=2; 3-2x, if x<2

I found the limits from left and right of 2 = -1 so the limit exists but I don't know how to figure out a

Answer 1

Am I missing something? If the limit from the left is -1, and the limit from the right is -1, and the function is continous, then the limit at the point is -1

Answer 2

So a=-1 That makes sense because it's continuous

Answer 3

to make it continuous f(2)=a so it would equal -1?