To find the surface area of a cylinder, we need to find the area of the two bases and the lateral surface area.
The formula for the area of a circle is A = πr^2, where r is the radius. Since the diameter is given as 12 inches, the radius is half of that, which is 6 inches.
The area of a circle with radius 6 inches is A = 3.14 * 6^2 = 113.04 in^2.
Next, we need to find the lateral surface area of the cylinder. The lateral surface area is the circumference of the base multiplied by the height of the cylinder.
The formula for the circumference of a circle is C = 2πr, where r is the radius.
The circumference of a circle with radius 6 inches is C = 2 * 3.14 * 6 = 37.68 inches.
The lateral surface area of the cylinder is L = C * h = 37.68 * 10 = 376.8 in^2.
Now, we can find the total surface area of the cylinder by adding the areas of the two bases and the lateral surface area.
Total surface area = 2(Area of base) + Lateral surface area
= 2(113.04) + 376.8
= 226.08 + 376.8
= 602.88 in^2
So, the surface area of the cylinder is approximately 602.88 in^2.
Find the surface area of a cylinder with a diameter of 12 inches and height of 10 inches. Use the approximation of 3.14 for pi.(1 point) in^2
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1 answer