Find the surface area of a cylinder with a diameter of 12 inches and height of 10 inches.

Answer 1

To find the surface area of a cylinder, we need to calculate the surface area of the two bases and the lateral surface area.

The surface area of a base of a cylinder is given by the formula $\pi r^2$, where $r$ is the radius of the base.

The radius of the base is half of the diameter, so it is $12/2=6$ inches.

The lateral surface area of a cylinder is given by the formula $2\pi rh$, where $r$ is the radius of the base and $h$ is the height.

The surface area of the two bases is $2 \cdot \pi \cdot 6^2 = 2 \cdot 36 \cdot \pi = 72\pi$ square inches.

The lateral surface area is $2\pi \times 6 \times 10 = 120\pi$ square inches.

Therefore, the total surface area of the cylinder is $72\pi + 120\pi = 192\pi$ square inches.

Since the value of $\pi$ is approximately 3.14, the surface area of the cylinder is approximately $192\cdot3.14 \approx \boxed{602.88}$ square inches.

Answer 2

Use the approximation of 3.14 for pi.

Answer 3

The surface area of the cylinder is $192\cdot3.14\approx \boxed{603.36}$ square inches.