I interpret that as the summation of 2n+1 for n = 1 to 14
so you have 14 terms ---> n = 14
term(1) = 2(1) + 1 = 3 , so a = 3
common difference is 2, d = 2
sum(14) = (14/2)(2(3) + 13(2)) = .... I see the correct answer in your choices
Find the sum of the following series. 14 n=1 (2n+1)
A. 448
B. 256
C. 240
D. 224
4 answers
Did you ever get the answer
yo anybody got the answer
its 224