The given sequence is a geometric sequence with the first term (a) = 3 and the common ratio (r) = 2.
The formula for the sum of the first n terms of a geometric sequence is:
S_n = a(1 - r^n) / (1 - r)
Substituting the given values, we get:
S_10 = 3(1 - 2^10) / (1 - 2)
S_10 = 3(1 - 1024) / (-1)
S_10 = -3(1023)
S_10 = -3069
Therefore, the sum of the first 10 terms of the given sequence is -3069.
Find the sum of the first 10 terms of the sequence:
3
,
6
,
12
,
24
,
…
3 answers
A geometric series with first term 3 converges to the sum of 2. Find the common ratio of the series
AAAaannndd the bot gets it wrong yet again!
ok until this step:
S_10 = 3(1 - 1024) / (-1)
S_10 = 3(-1023)
S_10 = 3069
it should have been obvious that the sum of positive terms could not be negative!
-------------------------------------------
3/(1-r) = 2
3/2 = 1-r
r = -1/2
ok until this step:
S_10 = 3(1 - 1024) / (-1)
S_10 = 3(-1023)
S_10 = 3069
it should have been obvious that the sum of positive terms could not be negative!
-------------------------------------------
3/(1-r) = 2
3/2 = 1-r
r = -1/2