Find the standard equation of the circle concentric with x^2+y^2-12x-10y = -12 and has a diameter of 10.

Question

I have been trying to solve this all day, can you please help me :(

Answer 1

x^2+y^2-12x-10y = -12
x^2 - 12x + 36 + y^2 - 10y + 25 = -12+36+25
(x-6)^2 + (y-5)^2) = 49

new circle needs a radius of 5, so

(x-6)^2 + (y-5)^2 = 25

Please tell me what you did to work on this "all day" .