Find the standard equation of a circle with the center (0, 2) and a radius of 2 units.
3 answers
(x-0)^2 + (y-2)^2 = 2^2
The standard equation of a circle is
(x-h)^2 + (y-k)^2 = r^2
Where h and k are the coordinates for the centre.
Hence(h, k) is (0, 2) respectively.
and the radius is 2 units
Now all you have to do is substitute it in.
(x-0)^2 + (y-2)^2 = 2^2
alas the standard equation is,
(x-2)^2 + (y-2)^2 = 4
(x-h)^2 + (y-k)^2 = r^2
Where h and k are the coordinates for the centre.
Hence(h, k) is (0, 2) respectively.
and the radius is 2 units
Now all you have to do is substitute it in.
(x-0)^2 + (y-2)^2 = 2^2
alas the standard equation is,
(x-2)^2 + (y-2)^2 = 4
Alas? All was good up till there.
The standard equation desired is indeed
x^2 + (y-2)^2 =4
The standard equation desired is indeed
x^2 + (y-2)^2 =4
1 answer