Find the speed and period of a satellite that orbits Mars 175 km above it's surface. (The average radius of Mars is 3.40 x 10^6; and it's mass is 6.42 x 10^23. Use all necessary formulas and show all clear-working, to enable me understand how you arrived at your answer.

Answer 1

If you check your formulas, you'll see

speed: v = √(GM/r)
period: T = 2π√(r^3/GM)

GM = 6.673 × 10^-11 x 6.42 x 10^23 = 4.284*10^13

v = √(4.284*10^13 / 3.40*10^6) = 3549.65 m/s
T = 2π√((3.4*10^6)^3/4.284*10^13) = 6018.30 sec