Scientists want to place a 3300 kg satellite in orbit around Mars. They plan to have the satellite orbit a distance equal to 2.2 times the radius of Mars above the surface of the planet. Here is some information that will help solve this problem:

Question

Scientists want to place a 3300 kg satellite in orbit around Mars. They plan to have the satellite orbit a distance equal to 2.2 times the radius of Mars above the surface of the planet. Here is some information that will help solve this problem:
mmars = 6.4191 x 1023 kg 
rmars = 3.397 x 106 m 
G = 6.67428 x 10-11 N-m2/kg2
1) What is the force of attraction between Mars and the satellite?

Damon · Answer

F = G M1 M2 / d^2 d = 2.2+1 = 3.2 mars radius=10.9*10^6 meters = 6.67*10^-11 (3300)(6.42*10^23)10^-12/(10.9)^2 = 1194 * 10^0 = 1194 Newtons