dy/dx = 4y/x^2
dy/y = 4/x^2 dx
lny = -4/x + c
y = c e^(-4/x)
Now use the condition to find c
Find the specific solution of the differential equation dy/dx = 4y/x^2 with condition y(−4) = e.
y equals negative 1 minus 4 divided by x
y equals negative 1 times e raised to the 1 over x power
y equals e raised to the negative 4 over x power
None of these
1 answer
1 answer