Find the specific solution of the differential equation dy/dx= 4y/x^2 with condition y(-4) = e.

1 answer

dy/dx= 4y/x^2
dy/y = 4/x^2 dx
lny = -4/x +c
y = c e^(-4/x)

c e^(-4/-4) = c*e = e
So, c=1

y = e^(-4/x)