dy/dx= 4y/x^2
dy/y = 4/x^2 dx
lny = -4/x +c
y = c e^(-4/x)
c e^(-4/-4) = c*e = e
So, c=1
y = e^(-4/x)
Find the specific solution of the differential equation dy/dx= 4y/x^2 with condition y(-4) = e.
1 answer
1 answer