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Find the slope of the tangent line to the curve y = (x^2 -8)^6 at x = 3, and

write the equation of the tangent line.

1 answer

Take the derivative.

y'=6(x^2-8)^5 * 2x

at x=3, put that in, and compute y'

equation: y=y' x + b
you have y'. you know x, and can compute y (original equation), so can compute b from that equation.
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