Find the related square root function, p(x)

, for the quadratic equation h(x)=4x2
with the domain of (0,∞)
.(1 point)
p(x)=ax−−√
where a=
Remaining Attempts : 3

2 answers

To find the related square root function \( p(x) \) for the quadratic equation \( h(x) = 4x^2 \) with the domain \( (0, \infty) \), we can express the function in terms of a square root.

The quadratic function \( h(x) = 4x^2 \) can be rewritten in terms of \( p(x) \) by taking the square root:

\[ p(x) = \sqrt{h(x)} = \sqrt{4x^2} \]

Simplifying this gives us:

\[ p(x) = 2x \]

Thus, we identify that:

\[ p(x) = ax \]

where \( a = 2 \).

So, for \( p(x) = ax \), we have:

\[ a = 2 \]

Final answer: \( a = 2 \)

this is wrong
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