Find the range of the function F(x)= integral from negative 6 to x of √(36-t^2) dt
5 answers
Karen /Alice -- please use the same name for your posts.
I will do it
I'm sure you can verify that
F(x) = x/2 √(36-x^2) - 9π
So the range is [-9,9] - 9π
F(x) = x/2 √(36-x^2) - 9π
So the range is [-9,9] - 9π
my teacher said I am wrong and he gave the options to choose:
a) [0,36pi]
b) [0,18pi]
c) [-6,6]
d) [-6,0]
Which one will be? PLEASE AND HOW
a) [0,36pi]
b) [0,18pi]
c) [-6,6]
d) [-6,0]
Which one will be? PLEASE AND HOW
It is b because the domain of the integral is from [-6,6], and plugging these numbers in results in a range from [0,18pi]
2 answers