Find the quadratic equation whose roots are given -2/3 and -1/4 with shown working below

3 answers

The quadratic equation is given by ax^2 + bx + c = 0, where a, b and c are constants.

We can use the formula for finding the quadratic equation given the roots:

a = 1, b = (root1 + root2), c = root1 * root2

Therefore, the quadratic equation is:

x^2 + ( (-2/3) + (-1/4) )x + (-2/3) * (-1/4) = 0

x^2 - 5/12x - 1/12 = 0
The quadratic equation is given by ax^2 + bx + c = 0, where a, b and c are constants.

We can use the formula for finding the quadratic equation given the roots:

a = 1, b = (root1 + root2), c = root1 * root2

Therefore, the quadratic equation is:

x^2 + ( (-2/3) + (-1/4) )x + (-2/3) * (-1/4) = 0

x^2 - 5/12x - 1/12 = 0
AAAaannndd the bot gets it wrong yet again!
TWICE!

(3x+2)(4x+1) = 0