find the point on the graph of y=x^2 where the tangent line is parallel to the line 2x-y=2

Answer 1

Y = X^2. 2X - Y = 2.

m = -A/B = -2 / -1 = 2 = Slope.

m2 = Y' = 2X = Slope of parabola.

Y' = 2X = 2,
2X = 2,
X = 1.

Y = X^2
Y = 1^2 = 1.

P(1, 1).

If you graph the parabola, you can use
the following points:

(-2,4), (-1,1), V(0,0), (1,1),(2,4).