Find the pH of a solution obtained by mixing 100cm3 of 01MHCl solution with 100cm3 of 0.2M NaOH

Answer 1

Convert volume to L

100cm^3=100mL=0.100L

Multiply your volume by the molarity given for each one and subtract moles of acid from moles of base.

looking at the numbers, I see that you are going to get more moles of base than acid, (i.e., 0.01 moles of NaOH. But double check.

molarity of unreacted NaOH=(0.01 moles of NaOH/total volume of acid and base used (0.2L)

plug in the value obtain from above in the below equation and solve for pH.

pOH=-log[OH-]

pH=14-pOH