To find the perimeter of a square, you use the formula:
\[ P = 4s \]
where \( s \) is the side length of the square. Given that the side length is \( \sqrt{332} \), we substitute this into the formula:
\[ P = 4\sqrt{332} \]
Next, we simplify \( \sqrt{332} \). First, we find the prime factorization of 332:
\[ 332 = 4 \times 83 \]
Now, we can simplify \( \sqrt{332} \):
\[ \sqrt{332} = \sqrt{4 \times 83} = \sqrt{4} \times \sqrt{83} = 2\sqrt{83} \]
Now substituting back into the perimeter formula:
\[ P = 4 \times 2\sqrt{83} = 8\sqrt{83} \]
Thus, the perimeter of the square is:
\[ \boxed{8\sqrt{83}} \]
Please note that none of the options provided in your initial list match the correct answer of \( 8\sqrt{83} \). Make sure to verify the side length or options given, as they may be incorrect.
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