The length of a side of a square is fifteen less than four times the length of a side of a second square. The perimeter of the two squares differ by 24 inches. Find in inches, the length of a side of the smaller square. [ Only an algebraic solution will be accepted ]

Answer 1

Try this one yourself by following a similar argument and solution like I just showed you in your previous post.
Hint: let x be the side of the first square and let y be the side of the second square.
Now express the English statements with algebraic equivalents.