Find the perimeter of a square with a side length of 2sqrt(12) Your answer must be in simplest radical form (point ) 8sqrt(12); 8sqrt(48); 32sqrt(3); 16sqrt(3)

1 answer

To find the perimeter of a square, you can use the formula:

\[ \text{Perimeter} = 4 \times \text{side length} \]

Given the side length of the square is \(2\sqrt{12}\), we can calculate the perimeter as follows:

\[ \text{Perimeter} = 4 \times (2\sqrt{12}) = 8\sqrt{12} \]

Next, we simplify \(8\sqrt{12}\).

First, simplify \(\sqrt{12}\):

\[ \sqrt{12} = \sqrt{4 \times 3} = \sqrt{4} \times \sqrt{3} = 2\sqrt{3} \]

Now plug this back into the perimeter calculation:

\[ 8\sqrt{12} = 8 \times 2\sqrt{3} = 16\sqrt{3} \]

Thus, the perimeter of the square in simplest radical form is:

\[ \boxed{16\sqrt{3}} \]