area of 9" pizza = 81π
area of 10" pizza = 100π
increase = 19π
percentage increase = 19π/(100π)(100%) = 19%
Find the percent increase in the area of a circular pizza if the radius is increased from nine inches to ten inches.
4 answers
A=r^2*pi
(10^2*pi)/(9^2*pi)=100/81=1.23456790123
1.23456790123*100%=123.456790123%
123.456790123%-100%=23.456790123%
increse=23.456790123%
(10^2*pi)/(9^2*pi)=100/81=1.23456790123
1.23456790123*100%=123.456790123%
123.456790123%-100%=23.456790123%
increse=23.456790123%
A = pi * r^2
A = 3.14 * 81
A = 254.34 sq. inches
Find the area of the larger pizza.
Divide the difference by the area of the smaller pizza.
A = 3.14 * 81
A = 254.34 sq. inches
Find the area of the larger pizza.
Divide the difference by the area of the smaller pizza.
I should have taken 19π/(81π) for a 23.5% increase
as 'anonymous" and Ms Sue did
sorry about that.
Time to get a strong coffee.
as 'anonymous" and Ms Sue did
sorry about that.
Time to get a strong coffee.