Ask a New Question
Search
Find the partial derivative for x.
f(x,y)=1/SQRTx^2+y^2
1 answer
treat y as a constant:
f(x,y) = (x^2 + y^2)^.5
dy/dx = .5 (x^2 + y^2)^-.5 * (2x)
= x/sqrt(x^2 + y^2)
Ask a New Question
or
answer this question
.
Similar Questions
Please check my answers and let me know if I did something wrong. Thank you!
Find the partial derivative of x, and the partial
1 answer
Evaluate: f(x,y)=2x^3e^y
a) partial derivative with respect to x. I know that you have to treat y as a constant but I have no
2 answers
y = tan(sqrtx)
Find dy/dx. So I found it and I got the answer as sec^2(sqrtx) but the answer is (sec^2(sqrtx))/2(sqrtx)...why?
2 answers
Find the indefinite integral of (1-sqrtx)/(1+sqrtx)dx
I just worked completely through this problem using substitution
2 answers
more similar questions