Find the numerical equivalent of 4 to the power of 9⋅4− to the power of 7(1 point)

Responses

16

4 to the power of 16

4
4 to the power of 2

1 answer

To find the numerical equivalent of \( 4^{9 \cdot 4^{-7}} \), we can simplify the expression step by step.

First, let's rewrite \( 4^{-7} \): \[ 4^{-7} = \frac{1}{4^7} \]

Now, we can rewrite \( 9 \cdot 4^{-7} \) as: \[ 9 \cdot 4^{-7} = \frac{9}{4^7} \]

Now calculate \( 4^{9 \cdot 4^{-7}} \): \[ 4^{9 \cdot 4^{-7}} = 4^{\frac{9}{4^7}} \]

Next, recall the laws of exponents which state \( a^{b^c} = a^{b \cdot c} \), so we can simplify this to: \[ 4^{\frac{9}{4^7}} = 4^{9} \cdot 4^{-7} \]

Thus, \[ 4^{9} \cdot 4^{-7} = 4^{9-7} = 4^{2} \]

Now we can translate \( 4^2 \) into its numerical form: \[ 4^2 = 16 \]

Therefore, the numerical equivalent of \( 4^{9 \cdot 4^{-7}} \) is: \[ \boxed{16} \]