Find the numerical equivalent of 2 to the power of 5 ⋅2 to the power of −2(1 point)

Question

128
16
2
8

Answer 1

To solve \(2^5 \cdot 2^{-2}\), we can use the property of exponents that states \(a^m \cdot a^n = a^{m+n}\).

Using this property, we combine the exponents:

\[ 2^5 \cdot 2^{-2} = 2^{5 + (-2)} = 2^{5 - 2} = 2^3 \]

Now, we need to find the numerical equivalent of \(2^3\):

\[ 2^3 = 2 \cdot 2 \cdot 2 = 8 \]

Thus, the numerical equivalent of \(2^5 \cdot 2^{-2}\) is \(\boxed{8}\).