Find the nth term and first three terms of the arithemetic sequence having u4=93 and u8=65.
2 answers
Answers
from your given:
a + 3d = 93
a + 7d = 65
subtract them:
4d = -28
d = -7
in a+3d = 93
a - 21 = 93
a = 114
You do the rest
a + 3d = 93
a + 7d = 65
subtract them:
4d = -28
d = -7
in a+3d = 93
a - 21 = 93
a = 114
You do the rest
4 answers