The torque produced by the 10 N force is
τ = 10 •0.23 = 2.3 (N•m),
The torque produced by the 9 N force is
τ = 9 •0.23 = 2.07 (N•m),
The torque produced by the 12 N force is
τ = 12 •0.11 = - 1.32 (N•m)
The total torque is
τ =2.3 + 2.07 -1.32 = 3.5 (N•m).
Find the net torque on the wheel in the figure below about the axle through O perpendicular to the page, taking a = 11.0 cm and b = 23.0 cm. (Indicate the direction with the sign of your answer. Assume that the positive direction is counterclockwise.)
8 answers
difficult
Elena is right you all just need to change the sign to negative
Elena did the right calcutions, she just got wrong the signs
The torque produced by the 10 N force is
τ = 10 • 0.23 = - 2.3 (N m),
The torque produced by the 9 N force is
τ = 9 • 0.23 = - 2.07 (N m),
The torque produced by the 12 N force is
τ = 12 • 0.11 = + 1.32 (N m)
The total torque is
τ =- 2.3 - 2.07 +1.32 = - 3.05 (N m)
The torque produced by the 10 N force is
τ = 10 • 0.23 = - 2.3 (N m),
The torque produced by the 9 N force is
τ = 9 • 0.23 = - 2.07 (N m),
The torque produced by the 12 N force is
τ = 12 • 0.11 = + 1.32 (N m)
The total torque is
τ =- 2.3 - 2.07 +1.32 = - 3.05 (N m)
Sup guys
Elena you need to do better
Cmon Elena
Pakopya guys, di ko magets si sir Daryl