Find the minimum and maximum values of the function f(x)= 2/3 sin pix on the interval [1,2] (domain).
I got (1.5, -2/3) as the minimum and no maximum on the interval. Is it correct? Thank you.
4 answers
correct.
I bet you mean
f(x) = (2/3) sin(pi x)
f'(x) = (2/3) pi cos(pi x)
f'(x) = 0 for max or min
that is when cos (pi x) = 0
x = 1/2 and x = 3/2
if x = 1/2
y = (2/3)sin (pi/2) = 2/3
if x = 3/2
y = (2/3) sin (3 pi/2) = -2/3
PS
You can be sure that the max and min of a sin function are +1 and -1
f(x) = (2/3) sin(pi x)
f'(x) = (2/3) pi cos(pi x)
f'(x) = 0 for max or min
that is when cos (pi x) = 0
x = 1/2 and x = 3/2
if x = 1/2
y = (2/3)sin (pi/2) = 2/3
if x = 3/2
y = (2/3) sin (3 pi/2) = -2/3
PS
You can be sure that the max and min of a sin function are +1 and -1
sorry, x = 1/2 not in domain so you are right
Thank you both! I appreciate it. :)
1 answer