5x-10=80 x=16
B=2(16) - 10 = 22
C= 3(16)+20 = 68
I'm not sure if that's right or not.
Find the longest side of triangle ABC, if measurement A=70, measurement B=2x-10, and measurement C=3x+20.
5 answers
I will assume that by "measurement A=70" you are referring to angle A
then 70 + 2x-10 + 3x+20 = 180
5x = 100
x = 20
then angle B = 30 and
angle C = 80
knowing that in any triangle, the largest side is opposite the largest angle, the largest side must be opposite angle C, which would be AB
then 70 + 2x-10 + 3x+20 = 180
5x = 100
x = 20
then angle B = 30 and
angle C = 80
knowing that in any triangle, the largest side is opposite the largest angle, the largest side must be opposite angle C, which would be AB
Find the pattern
Give the formula
0 -- 8
1 -- 11
2 -- 14
3 -- 17
4 --
5 --
50 --
n --
Give the formula
0 -- 8
1 -- 11
2 -- 14
3 -- 17
4 --
5 --
50 --
n --
y'all homies wrong
reiny is correct