Find the limit if it exists.

lim 1/(x-2) = infinity
x→2+

lim 1/(x-2) = negative infinity
x→2-

lim 1/(x-2) = Does not exist
x→2

lim (3x+2) = infinity
x→∞

lim 999/(x^3) = 0
x→-∞

Can someone check to make sure that I am correct?

1 answer

all look good
Similar Questions
  1. Find the horizontal asymptote off(x)=e^x - x lim x->infinity (e^x)-x= infinity when it's going towards infinity, shouldn't it
    1. answers icon 0 answers
    1. answers icon 1 answer
  2. Recall that a function G(x) has the limit L as x tends to infinity, writtenlim(x->infinity)G(x) = L, if for any epsilon > 0,
    1. answers icon 1 answer
  3. Recall that a function G(x) has the limit L as x tends to infinity, writtenlim(x->infinity)G(x) = L, if for any epsilon > 0,
    1. answers icon 1 answer
more similar questions