I assume that you mean H(x)= (x+4) / (3x-5)
x = (y+4)/ (3y-5)
(3y-5) x = y+4
3 x y - 5 x = y + 4
y - 3 x y = 4 - 5 x
y (1 - 3x) = (4-5x)
y = (4-5x)/(1-3x)
which is
y = (5x-4)/(3x-1)
Find the inverse of the function
H(x)= x+4/3x-5
2 answers
From Damon's
3 x y - 5 x = y + 4
3xy - y = 4 + 5x
y(3x - 1) = 4+5x
y = (5x + 4)/(3x - 1)
3 x y - 5 x = y + 4
3xy - y = 4 + 5x
y(3x - 1) = 4+5x
y = (5x + 4)/(3x - 1)