Ask a New Question
Menu

Find the integral

∫(x^2-6x+1)/(x^2+1) dx

2 answers

∫(x^2-6x+1)/(x^2+1) dx

=∫(x^2+1)dx/( x^2+1)-6∫xdx/( x^2+1)

= ∫dx - 6∫xdx/( x^2+1)
x - 6∫xdx/( x^2+1)

let z = x^2+1
dz = 2 x dx
so x dx = (1/2)dz
then
x - 6∫(1/2)dz/z

x - 3 ln z

x - 3 ln(x^2+1)
Similar Questions
  1. find integral using table of integrals )integral sin^4xdx this the formula i used integral sin^n xdx =-1/n sin^n-1xcosx +n-1/n
    1. answers icon 3 answers
  2. LEt f and g be continous functions with the following propertiesi. g(x) = A-f(x) where A is a constant ii. for the integral of 1
    1. answers icon 0 answers
  3. LEt f and g be continous functions with the following propertiesi. g(x) = A-f(x) where A is a constant ii. for the integral of 1
    1. answers icon 0 answers
  4. LEt f and g be continous functions with the following propertiesi. g(x) = A-f(x) where A is a constant ii. for the integral of 1
    1. answers icon 1 answer
more similar questions